博客
关于我
HDU 3007 Buried memory
阅读量:173 次
发布时间:2019-02-27

本文共 3527 字,大约阅读时间需要 11 分钟。

Buried memory

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 261    Accepted Submission(s): 139

Problem Description
Each person had do something foolish along with his or her growth.But,when he or she did this that time,they could not predict that this thing is a mistake and they will want this thing would rather not happened.
The world king Sconbin is not the exception.One day,Sconbin was sleeping,then swakened by one nightmare.It turned out that his love letters to Dufein were made public in his dream.These foolish letters might ruin his throne.Sconbin decided to destroy the letters by the military exercises's opportunity.The missile is the best weapon.Considered the execution of the missile,Sconbin chose to use one missile with the minimum destruction.
Sconbin had writen N letters to Dufein, she buried these letters on different places.Sconbin got the places by difficult,he wants to know where is the best place launch the missile,and the smallest radius of the burst area. Let's help Sconbin to get the award.
 

 

Input
There are many test cases.Each case consists of a positive integer N(N<500,^V^,our great king might be a considerate lover) on a line followed by N lines giving the coordinates of N letters.Each coordinates have two numbers,x coordinate and y coordinate.N=0 is the end of the input file.
 

 

Output
For each case,there should be a single line in the output,containing three numbers,the first and second are x and y coordinates of the missile to launch,the third is the smallest radius the missile need to destroy all N letters.All output numbers are rounded to the second digit after the decimal point.
 

 

Sample Input
31.00 1.002.00 2.003.00 3.000
 

 

Sample Output
2.00 2.00 1.41
 

 

Source
解题:
     
1.我们先照第一图画出两个圆,画完可知其余的点一定在两圆相交的椭圆里,因为距离就红线最长了,但是范围还是太大了;
2.再照第二个图画出第三个圆,我们可知,
   最完美的情况下,最长的线段即是要求的圆的直径,可以包含了所有的其余点,那么这些点就在红色的圆里面;
   非完美情况下,即有几个点在红圆的外面(不超出椭圆),那么红圆圆心到那些点最长的,定是所要求的圆的半径。画出第三个图。
(经
提醒,少考虑了等边三角形情况,现补充如下)
3.若是等边三角形,则圆心为等边三角形外心
本来都做对了,奈何一个函数名与系统的库函数冲突了,就是distance函数,CE了3次。
你可能感兴趣的文章
MySQL - ERROR 1406
查看>>
mysql - 视图
查看>>
MySQL - 解读MySQL事务与锁机制
查看>>
MTTR、MTBF、MTTF的大白话理解
查看>>
mt_rand
查看>>
mysql /*! 50100 ... */ 条件编译
查看>>
mudbox卸载/完美解决安装失败/如何彻底卸载清除干净mudbox各种残留注册表和文件的方法...
查看>>
mysql 1264_关于mysql 出现 1264 Out of range value for column 错误的解决办法
查看>>
mysql 1593_Linux高可用(HA)之MySQL主从复制中出现1593错误码的低级错误
查看>>
mysql 5.6 修改端口_mysql5.6.24怎么修改端口号
查看>>
MySQL 8.0 恢复孤立文件每表ibd文件
查看>>
MySQL 8.0开始Group by不再排序
查看>>
mysql ansi nulls_SET ANSI_NULLS ON SET QUOTED_IDENTIFIER ON 什么意思
查看>>
multi swiper bug solution
查看>>
MySQL Binlog 日志监听与 Spring 集成实战
查看>>
MySQL binlog三种模式
查看>>
multi-angle cosine and sines
查看>>
Mysql Can't connect to MySQL server
查看>>
mysql case when 乱码_Mysql CASE WHEN 用法
查看>>
Multicast1
查看>>